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Commercial Mathematics
Compound Interest
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- Definition: R.D. Account
- Maturity Period:
- Maturity Value (M.V.):
- Formula: Equivalent Principal for One Month
- Formula: Interest on R.D. Account
- Formula: Maturity Value (M.V.)
- Examples
Definition: Recurring Deposit Account (R.D. Account)
A scheme in which a fixed amount is deposited every month for a fixed period.
Definition: Maturity Period
Total time (in months/years) for which deposits are made.
Definition: Maturity Value (M.V.)
Total amount received at the end = Total deposits + Interest.
Formula: Interest on R.D.
\[I=P\times\frac{n(n+1)}{2\times12}\times\frac{r}{100}\]
Months = Years × 12
-
P = Monthly instalment
-
n = Number of months
-
r = Rate of interest (% p.a.)
-
I = Interest
-
M.V. = Maturity Value
Formula: Total Amount Deposited
Total Deposit = P × n
Formula: Maturity Value
M.V. = P × n + I
Shaalaa.com | Banking Example 1
Related QuestionsVIEW ALL [112]
A man holds a savings bank account in the union bank of India. A page of his passbook shows the following entries:
| Date | Particulars | Withdrawals (Rs) | Deposits (Rs) | Balance (Rs) |
| May 1 | B/F | 3,200.00 | ||
| May 6 | By Cheque | 500.00 | 3,700.00 | |
| May 17 | By Cheque | 800.00 | 4,500.00 | |
| June 4 | By Cash | 1,300.00 | 5,800.00 | |
| June 9 | To Cheque | 1,650.00 | 4,150.00 |
Calculate the rate of interest per annum if the total interest earned for the months of May and June is Rs. 39.25`
A page from the Savings Bank Account of Mr. Prateek is given below:
| Date | Particulars | Withdrawals (in ₹) |
Deposits (in ₹) |
Balance (in ₹) |
| January 1st, 2006 | B/F | - | - | 1,270 |
| January 7th, 2006 | By Cheque | - | 2,310 | 3,580 |
| March 9th, 2006 | To Self | 2,000 | - | 1,580 |
| March 26th, 2006 | By Cash | - | 6,200 | 7,780 |
| June 10th, 2006 | To Cheque | 4,500 | - | 3,280 |
| July 15th, 2006 | By Clearing | - | 2,630 | 5,910 |
| October 18th, 2006 | To Cheque | 530 | - | 5,380 |
| October 27th, 2006 | To Self | 2,690 | - | 2,690 |
| November 3rd, 2006 | By Cash | - | 1,500 | 4,190 |
| December 6th, 2006 | To Cheque | 950 | - | 3,240 |
| December 23rd, 2006 | By Transfer | - | 2,920 | 6,160 |
If he receives ₹198 as interest on 1st January 2007, find the rate of interest paid by the bank.
A page from the passbook of a savings book account in a particular year is given below:
| Date | Particulars | Debit (In Rs) | Credit (In Rs) | Balance (In Rs) |
| Jan 3 | By cash | 5,000.00 | 5,000.00 | |
| Feb 13 | To self | 500.00 | ||
| March 24 | By cheque | 2,000.00 | ||
| March 31 | By Interest | |||
| May 20 | By cash | 800.00 | ||
| July 7 | To Cheque | 1,400.00 | ||
| July 18 | By cash | 1,600.00 | ||
| Sept 15 | To Cheque | 3,200.00 | ||
| Sept 26 | By Cheque | 2,350.00 |
If the interest is calculated at 6% P.a. and is compounded at the end of march and September at every year, find the interest earned up to 31st march and then after completing all the entries, find the amount that the account holder would have received had he closed the account on 20th October the same year.
A page from a savings bank account passbook is given below:
| Date | Particulars | Amount withdrawn (Rs.) |
Amount Deposited (Rs.) |
Balance (Rs.) |
| Jan 7, 2016 | B/F | 3,000.00 | ||
| Jan 10, 2016 | By Cheque | 2600.00 | 5600.00 | |
| Feb 8, 2016 | To Self | 1500.00 | 4100.00 | |
| Apr 6, 2016 | By Cheque | 2100.00 | 2000.00 | |
| May 4, 2016 | By Cash | 6500.00 | 8500.00 | |
| May 27, 2016 | By Cheque | 1500.00 | 10000.00 |
1) Calculate the interest for the 6 months from January to June 2016, at 6% per annum.
2) If the account is closed on 1st July 2016, find the amount received by the account holder.
