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Chapters
1: Goods and Services Tax (G.S.T.)
2: Banking
3: Shares and Dividends
UNIT 2: ALGEBRA
4: Linear Inequations
5: Quadratic Equation
6: Problems on Quadratic Equations
7: Ratio and Proportion
8: Remainder Theorem and Factor Theorem
9: Matrices
10: Arithmetic Progression
11: Geometric Progression
12: Reflection
13: Section and Mid-point Formulae
▶ 14: Equation of a Straight Line
UNIT 3: GEOMETRY
Chapter 15: Similarity (As a Size Transformation)
Chapter 16: Similarity of Triangles
17: Loci
Chapter 18: Angle and Cyclic Properties of a Circle
Chapter 19: Tangent Properties of Circles
20: Constructions
UNIT 4: MENSURATION
Chapter 21: Volume and Surface Area of Solids (Cylinder, Cone and Sphere)
UNIT 5: TRIGONOMETRY
Chapter 22: Trigonometrical Identities
Chapter 23: Heights and Distances
UNIT 6: STATISTICS
Chapter 24: Graphical Representation of Statistical Data
Chapter 25: Measures of Central Tendency (Mean)
Chapter 26: Median, Quartiles and Mode
UNIT 7: PROBABILITY
Chapter 27: Probability
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Solutions for Chapter 14: Equation of a Straight Line
Below listed, you can find solutions for Chapter 14 of CISCE R.S. Aggarwal for Mathematics [English] Class 10 ICSE.
R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE 14 Equation of a Straight Line EXERCISE 14A [Pages 222 - 224]
Find the slope of the line passing through the points:
$$\mathrm{A}(-2, 1)$$ and $$\mathrm{B}(3, -4)$$
Find the slope of the line passing through the points:
$$\mathrm{A}(0, -3)$$ and $$\mathrm{B}(2, 1)$$
Find the slope of the line passing through the points:
$$\mathrm{A}(4, -9)$$ and $$\mathrm{B}(-2, -1)$$
Find the slope of the line passing through the points:
$$\mathrm{A}(2, 5)$$ and $$\mathrm{B}(-4, -4)$$
If the slope of the line joining $$\mathrm{P}(k, 3)$$ and $$\mathrm{Q}(8, -6)$$ is $$\frac{-3}{4}$$, find the value of $$k$$.
Without using distance formula, prove that the points A(1, 4), B(3, –2) and C(–3, 16) are collinear.
Find the value of $$k$$ such that the points $$\mathrm{P}(k, 1), \mathrm{Q}(2, -5)$$ and $$\mathrm{R}(k -2, -3)$$ are collinear.
Find the equation of a line parallel to $$x$$-axis and passing through the point (–3, 2).
Find the equation of a line parallel to $$y$$-axis and passing through the point (–7, 5).
Find the equation of a line whose inclination is $$30^{\circ}$$ and whose $$y$$-intercept is –2.
Find the equation of a line whose slope $$= \frac{3}{4}$$ and $$y$$-intercept $$= -4$$.
Find the equation of a line whose gradient $$= \sqrt{3}$$ and $$y$$-intercept $$= \frac{-2}{3}$$.
Find the equation of a line which makes an angle of $$60^{\circ}$$ with the positive direction of $$x$$-axis and passes through the point $$\mathrm{P}(0, -3)$$.
Find the equation of a line whose slope is 4 and which passes through the point (3, 7).
Find the equation of a line whose slope is – 3 and which passes through the point (–2, 3).
Find the gradient and the $$y$$-intercept of the following lines:
$$5x - 10y = 3$$
Find the gradient and the $$y$$-intercept of the following lines:
$$\frac{x}{6} + \frac{y}{9} = 1$$
Find the gradient and the $$y$$-intercept of the following lines:
$$x + 4 = 0$$
Find the gradient and the $$y$$-intercept of the following lines:
$$y = 6$$
Find the gradient and the equation of the line passing through the points:
$$\mathrm{A}(-2, 1)$$ and $$\mathrm{B}(3, -4)$$
Find the gradient and the equation of the line passing through the points:
$$\mathrm{A}(4, -2)$$ and $$\mathrm{B}(2, -3)$$
In the given diagram, ABC is a triangle, where B(4, – 4) and C(– 4, –2). D is a point on AC.
- Write down the coordinates of A and D.
- Find the coordinates of the centroid of ΔABC.
- If D divides AC in the ratio k : 1, find the value of k.
- Find the equation of the line BD.

A straight line passes through the points P(–1, 4) and Q(5, –2). It intersects $$x$$-axis and $$y$$-axis at the points A and B respectively and M is the mid-point of AB.
Find:
- the equation of the line;
- the co-ordinates of A and B;
- the co-ordinates of M.
$$\mathrm{A}(2,3)$$ and $$\mathrm{B}(-2,5)$$ are two given points.
Find:
- the gradient of AB;
- the equation of AB;
- the co-ordinates of the point, where AB intersects $$x$$-axis.
A straight line passes through the points A(2, – 4) and B(5, – 2).
Find:
- the slope of the line AB;
- the equation of the line AB;
- the value of $$k$$, if AB passes through the point $$\mathrm{P}(k + 3, k - 4)$$.
If A(3, 4), B(7, –2) and C(–2, –1) are the vertices of a $$\triangle \mathrm{ABC}$$, write down the equation of the median through the vertex C.
A(2, 5), B(–1, 2) and C(5, 8) are the vertices of a triangle ABC, M is a point on AB such that AM : MB = 1 : 2. Find the coordinates of M. Hence find the equation of the line passing through the points C and M.
The vertices of a $$\triangle \mathrm{ABC}$$ are A(2, –11), B(2, 13) and C(–12, 1). Find the equations of its sides.
[Hint. The slope of AB = `(13 + 11)/(2 - 2) = 24/0`, which is not defined.
∴ AB is parallel to y-axis. Its equation is x = а.
Also, it passes through (2, –11). So, a = 2. Hence, x = 2.]
ABC is a triangle whose vertices are A(1, –1), B(0, 4) and C(–6, 4). D is the midpoint of BC. Find the co-ordinates of D.
ABC is a triangle whose vertices are A(1, –1), B(0, 4) and C(– 6, 4). D is the midpoint of BC. Find the equation of the median AD.
Find the equation of a line passing through the point $$(2, 3)$$ and intersecting the line $$2x - 3y = 6$$ on the $$y$$-axis.
[Hint. 2x – 3у = 6 mеets y-axis at (0, –2). So, the required line passes through (0, –2).]
Find the equation of a line with $$x$$-intercept $$= 5$$ and passing through the point $$(4, -3)$$.
[Hint. The line passes through the points A(5, 0) and B(4, –3).]
Find the equations of the diagonals of a rectangle whose sides are: $$x = -1, x = 4$$, $$y = -1$$ and $$y = 2$$.
[Hint. The equations of sides in order are x = –1, y = –1, x = 4, y = 2. So, its vertices are A(–1, –1), B(4, –1), C(4, 2) and D(–1, 2).]
Find the equation of the line passing through the point $$(3, 2)$$ and making positive equal intercepts on axes. Find the length of each intercept.
[Hint. Let each intercept be a units.
Then, this line passes through A(a, 0) and B(0, a).
Equation of AB is `(y - 0)/(x - a) = (a - 0)/(0 - a) ⇒ y = -x + a.`
Since, it passes through (3, 2), we get a = 5.
∴ Required equation is x + y = 5.]
Find the equation of the line passing through the origin and the point of intersection of the lines $$5x + 7y = 3$$ and $$2x - 3y = 7$$.
[Hint: On solving 5x + 7y = 3 and 2x – 3y = 7, we get x = 2, y = –1. Now, find the equation of a line passing through the points A(2, –1) and O(0, 0).]
M and N are two points on the X axis and Y axis respectively. P (3, 2) divides the line segment MN in the ratio 2 : 3.
Find:
(i) the coordinates of M and N
(ii) slope of the line MN.
In what ratio does the line $$x - 5y + 15 = 0$$ divide the join of $$\mathrm{A}(2,1)$$ and $$\mathrm{B}(-3, 6)$$? Also, find the co-ordinates of their point of intersection.
[Hint. Let the given line divide AB in the ratio k : 1 at point P. Then, the co-ordinates of P would satisfy x – 5y + 15 = 0. Find k.]
Find the equations of the medians of $$\triangle \mathrm{ABC}$$ whose vertices are $$\mathrm{A}(-1, 2), \mathrm{B}(2, 1)$$ and $$\mathrm{C}(0, 4)$$. Hence, find the co-ordinates of the centroid of $$\triangle \mathrm{ABC}$$.
Find the coordinates of the centroid P of the ΔABC, whose vertices are A(–1, 3), B(3, –1) and C(0, 0). Hence, find the equation of a line passing through P and parallel to AB.
Three vertices of a parallelogram ABCD taken in order are A(3, 6), B(5, 10) and C(3, 2), find:
- the co-ordinates of the fourth vertex D.
- length of diagonal BD.
- equation of side AB of the parallelogram ABCD.
In the given figure, ABC is a triangle and BC is parallel to $$y$$-axis. AB and AC intersect the $$y$$-axis at P and Q respectively.
- Write the co-ordinates of A.
- Find the length of AB and AC.
- Find the ratio in which Q divides AC.
- Find the equation of the line AC.

R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE 14 Equation of a Straight Line EXERCISE 14B [Pages 231 - 233]
If $$\mathrm{A}(2, -3), \mathrm{B}(-5, 1), \mathrm{C}(7, -1)$$ and $$\mathrm{D}(0, k)$$ be four points such that AB is parallel to CD, find the value of $$k$$.
Show that the lines $$x + 2y - 5 = 0$$ and $$2x + 4y + 9 = 0$$ are parallel.
Find the value of $$k$$ for which the lines $$kx + 2y + 3 = 0$$ and $$8x + ky - 1 = 0$$ are parallel.
If the lines $$2x - by + 5 = 0$$ and $$ax + 3y = 2$$ are parallel, find the relation connecting $$a$$ and $$b$$.
Prove that the line through \(\mathrm{A}(-2, 6)\) and \(\mathrm{B}(4, 8)\) is perpendicular to the line through \(\mathrm{C}(8, 12)\) and \(\mathrm{D}(4, 24)\).
If $$\mathrm{A}(2, -5), \mathrm{B}(-2, 5), \mathrm{C}(k, 3)$$ and $$\mathrm{D}(1, 1)$$ be four points such that AB and CD are perpendicular to each other, find the value of $$k$$.
Prove that the lines 2x + 3y + 8 = 0 and 27x – 18y + 10 = 0 are perpendicular to each other.
If the lines y = 3x + 7 and 2y + px = 3 are perpendicular to each other, find the value of p.
If the straight lines 3x – 5y = 7 and 4x + ay + 9 = 0 are perpendicular to one another, find the value of a.
Without using Pythagoras Theorem, prove that the points \(\mathrm{A}(1, 3), \mathrm{B}(3, -1)\) and \(\mathrm{C}(-5, -5)\) are the vertices of a right-angled triangle.
[Hint: Show that \(\text{(Slope of AB)} \times (\text{slope of BC)} = -1\).]
Without using distance formula, show that the points A(1, –2), B(3, 6), C(5, 10) and D(3, 2) are the vertices of a parallelogram.
Given that A(5, 4), B(–3, –2) and C(1, –8) are the vertices of a $$\triangle \mathrm{ABC}$$.
Find:
- the slope of median AD,
- the slope of altitude BM.
Find the equation of the line parallel to the line 3x + 2y = 8 and passing through the point (0, 1).
Find the equation of a line parallel to the line $$2x + y - 7 = 0$$ and passing through the intersection of the lines $$x + y - 4 = 0$$ and $$2x - y = 8$$.
A(-1, 3), B(4, 2) and C(3, -2) are the vertices of a triangle.
1) Find the coordinates of the centroid G of the triangle
2) Find the equation of the line through G and parallel to AC
Find the equation of a line passing through the point $$\mathrm{P}(-2, 1)$$ and parallel to the line joining the points $$\mathrm{A}(4, -3)$$ and $$\mathrm{B}(-1, 5)$$.
If the lines kx – y + 4 = 0 and 2y = 6x + 7 are perpendicular to each other, find the value of k.
Find the equation of a line parallel to 2y = 6x + 7 and passing through (−1, 1).
Find the equation of the line passing through the origin and perpendicular to the line $$y + 5x = 3$$.
Find the equation of a line passing through the origin and parallel to the line $$3x - 2y + 4 = 0$$.
Find the equation of the line that has $$x$$-intercept – 3 and is perpendicular to the line $$3x + 5y = 1$$.
[Hint: The required line passes through $$(-3, 0)$$.]
Find the equation of the line passing through $$(2, 4)$$ and perpendicular to $$x$$-axis.
[Hint: Required line is parallel to $$y$$-axis.]
Find the equation of the perpendicular dropped from the point (−1, 2) onto the line joining the points (1, 4) and (2, 3).
Find the equation of the line passing through the point of intersection of the lines $$5x - 8y + 23 = 0$$ and $$7x + 6y - 71 = 0$$ and perpendicular to the line $$4x - 2y = 3$$.
A line through origin meets the line $$2x = 3y + 13$$ at right angles at point Q. Find the co-ordinates of Q.
[Hint. Find the co-ordinates of the foot of the perpendicular from $$P(0, 0)$$ to $$2x = 3y + 13$$.]
Find the equation of the perpendicular from the point $$\mathrm{P}(1, -2)$$ on the line $$4x - 3y - 5 = 0$$. Also, find the co-ordinates of the foot of the perpendicular.
Find the equation of the line which is perpendicular to the line $$\frac{x}{a} - \frac{y}{b} = 1$$ at the point where the given line meets $$y$$-axis.
Equation of a line AB is $$x + 2y + 6 = 0$$. A perpendicular PQ is dropped on AB from the point $$\mathrm{P}(3, -2)$$ meeting AB at Q. Find the:
- equation of PQ.
- coordinates of the point Q.
The points A(1, 3) and C(6, 8) are two opposite vertices of a square ABCD. Find the equation of the diagonal BD.
[Hint. $$BD$$ is the right-bisector of $$AC$$.]
A(1, 4), B(3, 2) and C(7, 5) are the vertices of a $$\triangle \mathrm{ABC}$$.
Find:
- the co-ordinates of the centroid G of $$\triangle \mathrm{ABC}$$,
- the equation of a line through G and parallel to AB.
A(– 4, 2), B(6, 4) and C(2, – 2) are the vertices of $$\triangle \mathrm{ABC}$$. Find the equation of median AD.
A(– 4, 2), B(6, 4) and C(2, – 2) are the vertices of $$\triangle \mathrm{ABC}$$. Find the equation of altitude BM.
A(– 4, 2), B(6, 4) and C(2, – 2) are the vertices of $$\triangle \mathrm{ABC}$$. Find the equation of right bisector of AB.
A(– 4, 2), B(6, 4) and C(2, – 2) are the vertices of $$\triangle \mathrm{ABC}$$. Find the co-ordinates of centroid of $$\triangle \mathrm{ABC}$$.
Find the equation of the perpendicular drawn from the point $$\mathrm{P}(2, 3)$$ on the line $$y = 3x + 4$$. Find the co-ordinates of the foot of the perpendicular.

[Hint: Let $$AB$$ be the line $$y = 3x + 4$$ and let $$PQ \perp AB$$.
Slope of $$PQ = \frac{-1}{\text {(Slope of AB)}} = \frac{-1}{3}$$.
Equation of $$PQ$$ is $$\frac{y - 3}{x - 2} = \frac{-1}{3} \Rightarrow x + 3y = 11$$.
On solving $$y = 3x + 4$$ and $$x + 3y = 11$$, we get co-ordinates of $$Q$$]
A(1, 2), B(2, 3) and C(4, 3) are the vertices of a $$\triangle \mathrm{ABC}$$.
Find:
- the equation of altitude through B;
- the equation of altitude through C;
- the co-ordinates of the orthocentre of $$\triangle \mathrm{ABC}$$.
$$\mathrm{A}(1, 2), \mathrm{B}(3, -4)$$ and $$\mathrm{C}(5, -6)$$ are the vertices of $$\triangle \mathrm{ABC}$$.
Find:
- the equation of the right bisector of BC;
- the equation of the right bisector of CA;
- the co-ordinates of the circumcentre of $$\triangle \mathrm{ABC}$$.
P is a point on the x-axis which divides the line joining A(–6, 2) and B(9, –4). Find:
- the ratio in which P divides the line segment AB.
- the coordinates of the point P.
- equation of a line parallel to AB and passing through (–3, –2).
A line segment AB meets $$x$$-axis at A and $$y$$-axis at B. P(4, –1) divides AB in the ratio 1 : 2.
- Find the co-ordinates of A and B.
- Find the equation of the line through P and perpendicular to AB.
The vertices of a $$\triangle \mathrm{ABC}$$ are A(3, 8), B(–1, 2) and C(6, –6).
Find:
- Slope of BC.
- Equation of a line perpendicular to BC and passing through A.
Line AB is perpendicular to CD. Co-ordinates of B, C and D are respectively (4, 0), (0, −1) and (4, 3). Find:
- slope of CD
- equation of AB

A and B are two points on the $$x$$-axis and $$y$$-axis respectively.

- Write down the coordinates of A and B.
- P is a point on AB such that $$\mathrm{AP} : \mathrm{PB} = 3 : 1$$. Using section formula, find the coordinates of point P.
- Find the equation of a line passing through P and perpendicular to AB.
A line segment joining P(2, –3) and Q(0, –1) is cut by the x-axis at the point R. A line AB cuts the y-axis at T(0, 6) and is perpendicular to PQ at S.
Find the:
- equation of line PQ
- equation of line AB
- coordinates of points R and S.
In the given graph ABCD is a parallelogram.

Using the graph, answer the following:
- write down the coordinates of A, B, C and D.
- calculate the coordinates of ‘P’, the point of intersection of the diagonals AC and BD.
- find the slope of sides CB and DA and verify that they represent parallel lines.
- find the equation of the diagonal AC.
R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE 14 Equation of a Straight Line COMPETENCY-FOCUSED QUESTIONS [Page 234]
I. Multiple Choice Questions Choose the correct alternative:
The inclination of every line parallel to the x-axis is ______.
0°
90°
180°
none of these
The inclination of y-axis is ______.
0°
45°
90°
180°
The slope of a line whose inclination is 30°, is ______.
\(\frac{1}{2}\)
\(\sqrt{3}\)
1
\(\frac{1}{\sqrt{3}}\)
The slope of a horizontal line is ______.
0
1
2
not defined
The slope of a vertical line is ______.
0
1
90
not defined
The slope of a line passing through two given points \(\mathrm{A}\left(x_{1}, y_{1}\right)\) and \(\mathrm{B}\left(x_{2}, y_{2}\right)\) is given by:
\(m = \frac{x_{2} - x_{1}}{y_{2} - y_{1}}\)
\(m = \frac{y_{2} \times y_{1}}{x_{2} \times x_{1}}\)
\(m = \frac{x_{2} \times x_{1}}{y_{2} \times y_{1}}\)
\(m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\)
Solutions for 14: Equation of a Straight Line
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R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE chapter 14 - Equation of a Straight Line
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