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Find the equation of the line passing through the origin and perpendicular to the line $$y + 5x = 3$$.

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Question

Find the equation of the line passing through the origin and perpendicular to the line $$y + 5x = 3$$.

Sum
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Solution

The given line is $$y + 5x = 3 \implies y = -5x + 3$$. 

Slope $$m_1 = -5$$.

The perpendicular line has slope:

$$m = -\frac{1}{m_1}$$

$$= -\frac{1}{-5}$$

$$= \frac{1}{5}$$

Passing through origin $$(0, 0)$$: 

$$y - 0 = \frac{1}{5}(x - 0)$$

$$5y = x$$

$$x - 5y = 0$$

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Chapter 14: Equation of a Straight Line - EXERCISE 14B [Page 231]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 14 Equation of a Straight Line
EXERCISE 14B | Q 16. (i) | Page 231
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