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प्रश्न
Find the equation of the line passing through the origin and perpendicular to the line $$y + 5x = 3$$.
योग
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उत्तर
The given line is $$y + 5x = 3 \implies y = -5x + 3$$.
Slope $$m_1 = -5$$.
The perpendicular line has slope:
$$m = -\frac{1}{m_1}$$
$$= -\frac{1}{-5}$$
$$= \frac{1}{5}$$
Passing through origin $$(0, 0)$$:
$$y - 0 = \frac{1}{5}(x - 0)$$
$$5y = x$$
$$x - 5y = 0$$
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अध्याय 14: Equation of a Straight Line - EXERCISE 14B [पृष्ठ २३१]
