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प्रश्न
Find the equation of a line passing through the origin and parallel to the line $$3x - 2y + 4 = 0$$.
योग
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उत्तर
The given line is $$3x - 2y + 4 = 0$$:
$$2y = 3x + 4$$
$$\implies y = \frac{3}{2}x + 2$$
Slope $$m = \frac{3}{2}$$.
The parallel line has the same slope $$m = \frac{3}{2}$$.
Passing through origin $$(0, 0)$$:
$$y - 0 = \frac{3}{2}(x - 0)$$
$$2y = 3x$$
$$3x - 2y = 0$$
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अध्याय 14: Equation of a Straight Line - EXERCISE 14B [पृष्ठ २३१]
