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Find the equation of the line which is perpendicular to the line $$\frac{x}{a} – \frac{y}{b} = 1$$ at the point where the given line meets $$y$$-axis.

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Question

Find the equation of the line which is perpendicular to the line $$\frac{x}{a} - \frac{y}{b} = 1$$ at the point where the given line meets $$y$$-axis.

Sum
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Solution

First find the point where the line meets the $$y$$-axis (put $$x = 0$$): 

$$\frac{0}{a} - \frac{y}{b} = 1$$

$$\implies -\frac{y}{b} = 1$$

$$\implies y = -b$$ 

So the point of intersection on the $$y$$-axis is $$(0, -b)$$.

Rewrite the equation to find its slope:

$$\frac{y}{b} = \frac{x}{a} - 1$$ 

$$y = \frac{b}{a}x - b$$ 

Slope of given line $$m_1 = \frac{b}{a}$$.

Slope of the perpendicular line:

$$m = -\frac{1}{m_1} = -\frac{a}{b}$$

Equation of the line passing through $$(0, -b)$$ with slope $$-\frac{a}{b}$$: 

$$y - (-b) = -\frac{a}{b}(x - 0)$$

$$y + b = -\frac{a}{b}x$$ 

$$b(y + b) = -ax$$ 

$$by + b^2 = -ax$$ 

$$ax + by + b^2 = 0$$

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Chapter 14: Equation of a Straight Line - EXERCISE 14B [Page 232]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 14 Equation of a Straight Line
EXERCISE 14B | Q 23. | Page 232
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