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Find the gradient and the equation of the line passing through the points: $$\mathrm{A}(4, –2)$$ and $$\mathrm{B}(2, –3)$$

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Question

Find the gradient and the equation of the line passing through the points:

$$\mathrm{A}(4, -2)$$ and $$\mathrm{B}(2, -3)$$

Sum
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Solution

The gradient of a line passing through $$(x_1, y_1)$$ and $$(x_2, y_2)$$ is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ and the equation of the line is $$y - y_1 = m(x - x_1)$$

For $$\mathrm{A}(4, -2)$$ and $$\mathrm{B}(2, -3)$$:

$$m = \frac{-3 - (-2)}{2 - 4}$$

$$= \frac{-3 + 2}{-2}$$

$$= \frac{-1}{-2}$$

$$= \frac{1}{2}$$

Equation of the line:

$$y - (-2) = \frac{1}{2}(x - 4)$$ 

$$y + 2 = \frac{1}{2}(x - 4)$$ 

$$2(y + 2) = x - 4$$ 

$$2y + 4 = x - 4$$ 

$$x - 2y - 8 = 0$$

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Chapter 14: Equation of a Straight Line - EXERCISE 14A [Page 223]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 14 Equation of a Straight Line
EXERCISE 14A | Q 11. (ii) | Page 223
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