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R.D. Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation [Latest edition]

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R.D. Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation - Shaalaa.com
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Solutions for Chapter 3: Rationalisation

Below listed, you can find solutions for Chapter 3 of CBSE R.D. Sharma for Mathematics [English] Class 9.


Exercise 3.1Exercise 3.2Exercise 3.3Exercise 3.4
Exercise 3.1 [Pages 2 - 3]

R.D. Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.1 [Pages 2 - 3]

1.1Page 2

Simplify of the following:

`root(3)4  xx root(3)16`

1.2Page 2

Simplify of the following:

`root(4)1250/root(4)2`

2.1Page 2

Simplify the following expressions:

`(4 + sqrt7)(3 + sqrt2)`

2.2Page 2

Simplify the following expressions:

`(3 + sqrt3)(5 - sqrt2)`

2.3Page 2

Simplify the following expressions:

`(sqrt5 - 2)(sqrt3 - sqrt5)`

3.1Page 2

Simplify the following expressions:

`(11 + sqrt11)(11 - sqrt11)`

3.2Page 2

Simplify the following expressions:

`(5 + sqrt7)(5 - sqrt7)`

3.3Page 2

Simplify the following expressions:

`(sqrt8 - sqrt2)(sqrt8 + sqrt2)`

3.4Page 2

Simplify the following expressions:

`(3 + sqrt3)(3 - sqrt3)`

3.5Page 2

Simplify the following expression:

`(sqrt5 - sqrt2)(sqrt5 + sqrt2)`

4.1Page 3

Simplify the following expressions:

`(sqrt3 + sqrt7)^2`

4.2Page 3

Simplify the following expressions:

`(sqrt5 - sqrt3)^2`

4.3Page 3

Simplify the following expressions:

`(2sqrt5 + 3sqrt2)^2`

Exercise 3.2 [Pages 14 - 15]

R.D. Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.2 [Pages 14 - 15]

1.1Page 14

Rationalise the denominator of each of the following

`3/sqrt5`

1.2Page 14

Rationalise the denominator of the following:

`3/(2sqrt5)`

1.3Page 14

Rationalise the denominator of each of the following 

`1/sqrt12`

1.4Page 14

Rationalise the denominator of the following

`sqrt2/sqrt5`

1.5Page 14

Rationalise the denominator of the following

`(sqrt3 + 1)/sqrt2`

1.6Page 14

Rationalise the denominator of the following

`(sqrt2 + sqrt5)/3`

1.7Page 14

Rationalise the denominator of the following 

`(3sqrt2)/sqrt5`

2.1Page 14

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`2/sqrt3`

2.2Page 14

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`3/sqrt10`

2.3Page 14

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`(sqrt5 + 1)/sqrt2`

2.4Page 14

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`(sqrt10 + sqrt15)/sqrt2`

`

2.5Page 14

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`(2 + sqrt3)/3`

2.6Page 14

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`(sqrt2 - 1)/sqrt5`

3.1Page 14

Express the following with rational denominator:

`1/(3 + sqrt2)`

3.2Page 14

Express of the following with rational denominator:

`1/(sqrt6 - sqrt5)`

3.3Page 14

Express the following with rational denominator:

`16/(sqrt41 - 5)`

3.4Page 14

Express the following with rational denominator:

`30/(5sqrt3 - 3sqrt5)`

3.5Page 14

Express the following with rational denominator:

`1/(2sqrt5 - sqrt3)`

3.6Page 14

Express the following with rational denominator:

`(sqrt3 + 1)/(2sqrt2 - sqrt3)`

3.7Page 14

Express the following with rational denominator:

`(6 - 4sqrt2)/(6 + 4sqrt2)`

3.8Page 14

Express the following with rational denominator:

`(3sqrt2 + 1)/(2sqrt5 - 3)`

3.9Page 14

Express each one of the following with rational denominator:

`(b^2)/(sqrt(a^2 + b^2) + a)`

4.1Page 14

Rationales the denominator and simplify:

`(3 - sqrt2)/(3 + sqrt2)`

4.2Page 14

Rationales the denominator and simplify:

`(5 + 2sqrt3)/(7 + 4sqrt3)`

4.3Page 14

Rationales the denominator and simplify:

`(1 + sqrt2)/(3 - 2sqrt2)`

4.4Page 14

Rationales the denominator and simplify:

`(2sqrt6 - sqrt5)/(3sqrt5 - 2sqrt6)`

4.5Page 14

Rationales the denominator and simplify:

`(4sqrt3 + 5sqrt2)/(sqrt48 + sqrt18)`

4.6Page 14

Rationales the denominator and simplify:

`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`

5.1Page 14

Simplify:

`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`

5.2Page 14

Simplify

`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`

5.3Page 14

Simplify:

`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`

6.1Page 14

In the following determine rational numbers a and b:

`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`

6.2Page 14

In the following determine rational numbers a and b:

`(4 + sqrt2)/(2 + sqrt2) = n - sqrtb`

6.3Page 14

In the following determine rational numbers a and b:

`(3 + sqrt2)/(3 - sqrt2) = a + bsqrt2`

6.4Page 14

In the following determine rational numbers a and b:

`(5 + 3sqrt3)/(7 + 4sqrt3) = a + bsqrt3`

6.5Page 14

In the following determine rational numbers a and b:

`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`

6.6Page 14

In the following determine rational numbers a and b:

`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`

7Page 15

Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and  `sqrt5 = 2.236`

8.1Page 15

Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`

`(3 - sqrt5)/(3 + 2sqrt5)`

8.2Page 15

Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`

`(1 + sqrt2)/(3 - 2sqrt2)`

9.1Page 15

Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]

9.2Page 15

Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]

10Page 15

if `x = 2 +  sqrt3`,find the value of `x^2 + 1/x^2`

11Page 15

if   `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`

12Page 15

if `x =  (sqrt3 + 1)/2` find the value of `4x^2 +2x^2 - 8x + 7` 

Exercise 3.3 [Page 16]

R.D. Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.3 [Page 16]

1Page 16

Write the value of \[\left( 2 + \sqrt{3} \right) \left( 2 - \sqrt{3} \right) .\]

 

2Page 16

Write the reciprocal of \[5 + \sqrt{2}\].

3Page 16

Write the rationalisation factor of \[7 - 3\sqrt{5}\].

4Page 16

If\[\frac{\sqrt{3} - 1}{\sqrt{3} + 1} = x + y\sqrt{3},\]  find the values of and y.

5Page 16

If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]

6Page 16

If \[a = \sqrt{2} + 1\],then find the value of  \[a - \frac{1}{a}\].

7Page 16

If \[x = 2 + \sqrt{3}\] ,  find the value of \[x + \frac{1}{x}\].

8Page 16

Write the rationalisation factor of \[\sqrt{5} - 2\].

9Page 16

Simplify \[\sqrt{3 + 2\sqrt{2}}\].

10Page 16

Simplify \[\sqrt{3 - 2\sqrt{2}}\].

11Page 16

If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].

Exercise 3.4 [Pages 16 - 18]

R.D. Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.4 [Pages 16 - 18]

1Page 16

\[\sqrt{10} \times \sqrt{15}\] is equal to

  • 5\[\sqrt{6}\]

  • 6\[\sqrt{5}\]

  • \[\sqrt{30}\]

  • \[\sqrt{25}\]

2Page 16

\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to

  • \[\sqrt[5]{36}\]

  • \[\sqrt[5]{6 \times 0}\]

  • \[\sqrt[5]{6}\]

  • \[\sqrt[5]{12}\]

3Page 16

The rationalisation factor of \[\sqrt{3}\] is 

  • \[- \sqrt{3}\]

  • \[\frac{1}{\sqrt{3}}\]

  • \[2\sqrt{3}\]

  • \[- 2\sqrt{3}\]

4Page 17

The rationalisation factor of \[2 + \sqrt{3}\] is 

  • \[2 - \sqrt{3}\]

  • \[2 + \sqrt{3}\]

  • \[\sqrt{2} - 3\]

  • \[\sqrt{3} - 2\]

5Page 17

If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals

  • \[2\sqrt{5}\]

  • 4

  • 2

  • \[\sqrt{5}\]

6Page 17

If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then

  • a = 2, b =1

  • a = 2, b =−1

  • a = −2, b = 1

  • a = b = 1

7Page 17

The simplest rationalising factor of  \[\sqrt[3]{500}\] is 

  • \[\sqrt[3]{2}\]

  • \[\sqrt[3]{5}\]

  • \[\sqrt{3}\]

  • none of these

8Page 17

The simplest rationalising factor of \[\sqrt{3} + \sqrt{5}\] is ______.

  • `sqrt3 - 5`

  • `3 - sqrt5`

  • `sqrt3 - sqrt5`

  • `sqrt3 + sqrt5`

9Page 17

The simplest rationalising factor of \[2\sqrt{5}-\]\[\sqrt{3}\] is 

  • \[2\sqrt{5} + 3\]

  • \[2\sqrt{5} + \sqrt{3}\]

  • \[\sqrt{5} + \sqrt{3}\]

  • \[\sqrt{5} - \sqrt{3}\]

10Page 17

If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =

  • 1

  • 3

  • 6

  • 7

11Page 17

If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]

  • 64

  • 134

  • 194

  • 1/49

12Page 17

If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] = 

  • 2

  • 4

  • 8

  • 1

13Page 17

If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=

  • 9

  • 5

  • 17

  • 7

14Page 17

If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x2 + y +y2 =

  • 101

  • 99

  • 98

  • 102

15Page 17

\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to

  • \[3 + 2\sqrt{2}\]

  • \[\frac{1}{3 + 2\sqrt{2}}\]

  • \[3 - 2\sqrt{2}\]

  • \[\frac{3}{2} - \sqrt{2}\]

16Page 17

The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is 

  • \[\frac{4}{3}\]

  • 4

  • 3

  • `3/4`

17Page 17

If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then

  •  x = 13, y = −7

  • x = −13, y = 7

  • x = −13, y =- 7

  • x = 13, y = 7

18Page 17

If x = \[\sqrt[3]{2 + \sqrt{3}}\] , then \[x^3 + \frac{1}{x^3} =\]

  • 2

  • 4

  • 8

  • 9

19Page 17

The value of \[\sqrt{3 - 2\sqrt{2}}\] is 

  • \[\sqrt{2} - 1\]

  • \[\sqrt{2} + 1\]

  • \[\sqrt{3} - \sqrt{2}\]

  • \[\sqrt{3} + \sqrt{2}\]

20Page 18

The value of \[\sqrt{5 + 2\sqrt{6}}\] is

  • \[\sqrt{3} - \sqrt{2}\]

  • \[\sqrt{3} + \sqrt{2}\]

  • \[\sqrt{5} + \sqrt{6}\]

  • none of these

21Page 18

If \[\sqrt{2} = 1 . 4142\] then \[\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\] is equal to

  • 0.1718

  •  5.8282

  •  0.4142

  • 2.4142

22Page 18

If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is

  •  0.235

  • 0.707

  • 1.414

  • 0.471

23Page 18

The positive square root of \[7 + \sqrt{48}\] is 

  • \[7 + 2\sqrt{3}\]

  • \[7 + \sqrt{3}\]

  • \[ \sqrt{3}+2\]

  • \[3 + \sqrt{2}\]

24Page 18

If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]

  • \[2\sqrt{6}\]

  • \[2\sqrt{5}\]

  • 24

  • 20

25Page 18

If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]

  • −5

  • −6

  • −4

  • −2

Solutions for 3: Rationalisation

Exercise 3.1Exercise 3.2Exercise 3.3Exercise 3.4
R.D. Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation - Shaalaa.com

R.D. Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation

Shaalaa.com has the CBSE Mathematics Mathematics [English] Class 9 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.D. Sharma solutions for Mathematics Mathematics [English] Class 9 CBSE 3 (Rationalisation) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. R.D. Sharma textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 9 chapter 3 Rationalisation are Concept of Real Numbers, Irrational Numbers and Proof of Irrationality, Real Numbers and Their Decimal Expansions, Operations on Real Numbers, Laws of Exponents for Real Numbers, Representing Real Numbers on the Number Line.

Using R.D. Sharma Mathematics [English] Class 9 solutions Rationalisation exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in R.D. Sharma Solutions are essential questions that can be asked in the final exam. Maximum CBSE Mathematics [English] Class 9 students prefer R.D. Sharma Textbook Solutions to score more in exams.

Get the free view of Chapter 3, Rationalisation Mathematics [English] Class 9 additional questions for Mathematics Mathematics [English] Class 9 CBSE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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