Advertisements
Advertisements
Question
Write the rationalisation factor of \[\sqrt{5} - 2\].
Advertisements
Solution
Given that,`sqrt5 - 2` we know that rationalization factor of `sqrta - b` is `sqrta + b`
So the rationalization factor of `sqrt5 - 2`is `sqrt5 +2`.
APPEARS IN
RELATED QUESTIONS
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
Rationales the denominator and simplify:
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
Write the value of \[\left( 2 + \sqrt{3} \right) \left( 2 - \sqrt{3} \right) .\]
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
Simplify the following expression:
`(sqrt5+sqrt2)^2`
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
