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प्रश्न
Write the rationalisation factor of \[\sqrt{5} - 2\].
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उत्तर
Given that,`sqrt5 - 2` we know that rationalization factor of `sqrta - b` is `sqrta + b`
So the rationalization factor of `sqrt5 - 2`is `sqrt5 +2`.
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संबंधित प्रश्न
Simplify the following expressions:
`(sqrt3 + sqrt7)^2`
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Rationales the denominator and simplify:
`(3 - sqrt2)/(3 + sqrt2)`
Rationales the denominator and simplify:
`(5 + 2sqrt3)/(7 + 4sqrt3)`
Simplify \[\sqrt{3 - 2\sqrt{2}}\].
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
Classify the following number as rational or irrational:
`(3+sqrt23)-sqrt23`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
