Advertisements
Advertisements
प्रश्न
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Advertisements
उत्तर
We know that rationalization factor for `sqrt(a^2 + b^2) + a` is `sqrt(a^2 + b^2) - a`. We will multiply numerator and denominator of the given expression `b^2/(sqrt(a^2 + b^2) + a) ` by `sqrt(a^2 + b^2) - a` to get
`b^2/(sqrt(a^2 + b^2) + a) xx (sqrt(a^2 + b^2) - a)/(sqrt(a^2 + b^2) - a) = (b^2(sqrt(a^2 + b^2)))/(sqrt(a^2 + b^2) - a^2)`
`= (b^2 (sqrt(a^2 + b^2) - a))/(a^2 + b^2 - a^2)`
`= (b^2(sqrt(a^2 + b^2) - a))/b^2`
`= sqrt(a^2 + b^2) - a`
Hence the given expression is simplified with rational denominator to `sqrt(a^2 + b^2) - a`
APPEARS IN
संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Simplify the following expressions:
`(11 + sqrt11)(11 - sqrt11)`
Simplify the following expressions:
`(3 + sqrt3)(3 - sqrt3)`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt10 + sqrt15)/sqrt2`
`
Rationales the denominator and simplify:
`(4sqrt3 + 5sqrt2)/(sqrt48 + sqrt18)`
Simplify:
`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
Rationalise the denominator of the following:
`1/(sqrt7-2)`
`root(4)root(3)(2^2)` equals to ______.
Simplify the following:
`4sqrt(28) ÷ 3sqrt(7) ÷ root(3)(7)`
