Advertisements
Advertisements
प्रश्न
Simplify the following:
`3sqrt(3) + 2sqrt(27) + 7/sqrt(3)`
Advertisements
उत्तर
`3sqrt(3) + 2sqrt(27) + 7/sqrt(3) = 3sqrt(3) + 2sqrt(3 xx 3 xx 3) + 7/sqrt(3) xx sqrt(3)/sqrt(3)`
= `3sqrt(3) + 6sqrt(3) + (7sqrt(3))/3`
= `9sqrt(3) + (7sqrt(3))/3`
= `(27sqrt(3) + 7sqrt(3))/3`
= `(34sqrt(3))/3`
APPEARS IN
संबंधित प्रश्न
Express the following with rational denominator:
`16/(sqrt41 - 5)`
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
Write the rationalisation factor of \[\sqrt{5} - 2\].
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
Simplify the following expression:
`(sqrt5-sqrt2)(sqrt5+sqrt2)`
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
If `x = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))` and `y = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2))`, then find the value of x2 + y2.
