Advertisements
Advertisements
प्रश्न
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Advertisements
उत्तर
We know that rationalization factor for `sqrt41 - 5` is `sqrt41 + 5` to get
`16/(sqrt41 - 5) xx (sqrt41 + 5)/((sqrt41)^2 - (5)^2)`
`= (16(sqrt41) + 5)/(41- 25)`
`= (16(sqrt41 + 5))/16`
`= sqrt41 + 5`
Hence the given expression is simplified with rational denominator to `sqrt41+5`
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(5 + sqrt7)(5 - sqrt7)`
Rationalise the denominator of each of the following
`3/sqrt5`
Rationalise the denominator of each of the following
`1/sqrt12`
Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]
Write the rationalisation factor of \[\sqrt{5} - 2\].
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
Simplify the following expression:
`(sqrt5-sqrt2)(sqrt5+sqrt2)`
Simplify the following:
`(2sqrt(3))/3 - sqrt(3)/6`
Rationalise the denominator of the following:
`(2 + sqrt(3))/(2 - sqrt(3))`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
