Advertisements
Advertisements
प्रश्न
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Advertisements
उत्तर
We know that rationalization factor for `sqrt41 - 5` is `sqrt41 + 5` to get
`16/(sqrt41 - 5) xx (sqrt41 + 5)/((sqrt41)^2 - (5)^2)`
`= (16(sqrt41) + 5)/(41- 25)`
`= (16(sqrt41 + 5))/16`
`= sqrt41 + 5`
Hence the given expression is simplified with rational denominator to `sqrt41+5`
APPEARS IN
संबंधित प्रश्न
Express the following with rational denominator:
`30/(5sqrt3 - 3sqrt5)`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Rationales the denominator and simplify:
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`
Simplify `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + sqrt12/(sqrt3 - sqrt2)`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
\[\sqrt{10} \times \sqrt{15}\] is equal to
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
If `x = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))` and `y = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2))`, then find the value of x2 + y2.
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
