Advertisements
Advertisements
प्रश्न
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Advertisements
उत्तर
We know that rationalization factor for `sqrt41 - 5` is `sqrt41 + 5` to get
`16/(sqrt41 - 5) xx (sqrt41 + 5)/((sqrt41)^2 - (5)^2)`
`= (16(sqrt41) + 5)/(41- 25)`
`= (16(sqrt41 + 5))/16`
`= sqrt41 + 5`
Hence the given expression is simplified with rational denominator to `sqrt41+5`
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(3 + sqrt3)(5 - sqrt2)`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt5 + 1)/sqrt2`
Rationales the denominator and simplify:
`(4sqrt3 + 5sqrt2)/(sqrt48 + sqrt18)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
if `x = 2 + sqrt3`,find the value of `x^2 + 1/x^2`
If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
