Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Advertisements
उत्तर
We know that rationalization factor for `1/sqrta` is `sqrta`. We will multiply numerator and denominator of the given expression `(sqrt2 + sqrt5)/sqrt3` by `sqrt3` to get
`(sqrt2 + sqrt5)/sqrt3 " by " sqrt3` to get
`(sqrt2 + sqrt5)/sqrt3 xx sqrt3/sqrt3 = (sqrt2 xx sqrt3 + sqrt5 xx sqrt3)/(sqrt3 xx sqrt3)`
`= (sqrt6 + sqrt15)/3`
Hence the given expression is simplified to `(sqrt6 +sqrt15)/3`
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(sqrt8 - sqrt2)(sqrt8 + sqrt2)`
Rationales the denominator and simplify:
`(2sqrt6 - sqrt5)/(3sqrt5 - 2sqrt6)`
Simplify
`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`
If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then
`1/(sqrt(9) - sqrt(8))` is equal to ______.
Simplify the following:
`3/sqrt(8) + 1/sqrt(2)`
Rationalise the denominator of the following:
`sqrt(40)/sqrt(3)`
Find the value of a and b in the following:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
Simplify:
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2))`
