Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following
`(3sqrt2)/sqrt5`
Advertisements
उत्तर
We know that rationalization factor for `1/sqrta` is `sqrta`. We will multiply numerator and denominator of the given expression `(3sqrt2)/sqrt5` by `sqrt5` to get
`(3sqrt2)/sqrt5 xx sqrt5/sqrt5 = (3sqrt2 xx sqrt5)/(sqrt5 xx sqrt5)`
`= (3sqrt10)/5`
Hence the given expression is simplified to `(3sqrt10)/5`.
APPEARS IN
संबंधित प्रश्न
Simplify the following expression:
`(3+sqrt3)(2+sqrt2)`
Simplify the following expressions:
`(5 + sqrt7)(5 - sqrt7)`
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Rationales the denominator and simplify:
`(2sqrt6 - sqrt5)/(3sqrt5 - 2sqrt6)`
In the following determine rational numbers a and b:
`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
Simplify `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + sqrt12/(sqrt3 - sqrt2)`
\[\sqrt{10} \times \sqrt{15}\] is equal to
Classify the following number as rational or irrational:
2π
Simplify the following expression:
`(sqrt5-sqrt2)(sqrt5+sqrt2)`
