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प्रश्न
Rationalise the denominator of the following
`(3sqrt2)/sqrt5`
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उत्तर
We know that rationalization factor for `1/sqrta` is `sqrta`. We will multiply numerator and denominator of the given expression `(3sqrt2)/sqrt5` by `sqrt5` to get
`(3sqrt2)/sqrt5 xx sqrt5/sqrt5 = (3sqrt2 xx sqrt5)/(sqrt5 xx sqrt5)`
`= (3sqrt10)/5`
Hence the given expression is simplified to `(3sqrt10)/5`.
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संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Simplify the following expressions:
`(3 + sqrt3)(3 - sqrt3)`
Rationalise the denominator of the following
`sqrt2/sqrt5`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
Simplify \[\sqrt{3 - 2\sqrt{2}}\].
Simplify the following:
`(2sqrt(3))/3 - sqrt(3)/6`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
