Advertisements
Advertisements
प्रश्न
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
Advertisements
उत्तर
We know that rationalization factor of the denominator is `sqrt10`. We will multiply numberator and denominator of the given expression `3/sqrt10` by `sqrt10to get
`3/sqrt10 xx sqrt10/sqrt10 = (3 xx sqrt10)/(sqrt10 xx sqrt10)`
`= (3sqrt10)/10`
`= (3 xx 3.162)/10`
`= 9.486/10`
= 0.9486
The value of expression 0.9486 can be round off to three decimal places as 0.949.
Hence the given expression is simplified to 0.949.
APPEARS IN
संबंधित प्रश्न
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Simplify:
`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Rationalise the denominator of the following:
`(2 + sqrt(3))/(2 - sqrt(3))`
If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`.
If `x = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))` and `y = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2))`, then find the value of x2 + y2.
