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प्रश्न
Write the rationalisation factor of \[\sqrt{5} - 2\].
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उत्तर
Given that,`sqrt5 - 2` we know that rationalization factor of `sqrta - b` is `sqrta + b`
So the rationalization factor of `sqrt5 - 2`is `sqrt5 +2`.
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संबंधित प्रश्न
Simplify of the following:
`root(3)4 xx root(3)16`
Simplify the following expression:
`(sqrt5 - sqrt2)(sqrt5 + sqrt2)`
Rationales the denominator and simplify:
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
Simplify the following expression:
`(3+sqrt3)(3-sqrt3)`
Simplify the following:
`sqrt(24)/8 + sqrt(54)/9`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Find the value of a and b in the following:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`1/(sqrt(3) + sqrt(2))`
If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`.
