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प्रश्न
Write the rationalisation factor of \[\sqrt{5} - 2\].
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उत्तर
Given that,`sqrt5 - 2` we know that rationalization factor of `sqrta - b` is `sqrta + b`
So the rationalization factor of `sqrt5 - 2`is `sqrt5 +2`.
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संबंधित प्रश्न
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Simplify the following expressions:
`(3 + sqrt3)(3 - sqrt3)`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(1 + sqrt2)/(3 - 2sqrt2)`
The rationalisation factor of \[\sqrt{3}\] is
If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then
Find the value of a and b in the following:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`
Simplify:
`(256)^(-(4^((-3)/2))`
