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प्रश्न
Write the rationalisation factor of \[\sqrt{5} - 2\].
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उत्तर
Given that,`sqrt5 - 2` we know that rationalization factor of `sqrta - b` is `sqrta + b`
So the rationalization factor of `sqrt5 - 2`is `sqrt5 +2`.
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संबंधित प्रश्न
Simplify the following expression:
`(sqrt5 - sqrt2)(sqrt5 + sqrt2)`
Express the following with rational denominator:
`(3sqrt2 + 1)/(2sqrt5 - 3)`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
If \[a = \sqrt{2} + 1\],then find the value of \[a - \frac{1}{a}\].
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`.
