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प्रश्न
Write the rationalisation factor of \[\sqrt{5} - 2\].
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उत्तर
Given that,`sqrt5 - 2` we know that rationalization factor of `sqrta - b` is `sqrta + b`
So the rationalization factor of `sqrt5 - 2`is `sqrt5 +2`.
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संबंधित प्रश्न
Rationalise the denominator of each of the following
`1/sqrt12`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
In the following determine rational numbers a and b:
`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
Classify the following number as rational or irrational:
`1/sqrt2`
Simplify the following:
`3sqrt(3) + 2sqrt(27) + 7/sqrt(3)`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Rationalise the denominator of the following:
`(4sqrt(3) + 5sqrt(2))/(sqrt(48) + sqrt(18))`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
