Advertisements
Advertisements
प्रश्न
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
विकल्प
\[2\sqrt{5}\]
4
2
\[\sqrt{5}\]
Advertisements
उत्तर
Given that. `x=sqrt5 +2 ` Hence `1/x`is given as
`1/x = 1/(sqrt5+2)`.We need to find `x - 1/x`
We know that rationalization factor for `sqrt5+2` is`sqrt5-2`. We will multiply numerator and denominator of the given expression\`1/(sqrt5 +2)` by`sqrt5 - 2`, to get
`1/x = 1/(sqrt5+2 ) xx (sqrt5 - 2)/(sqrt5 -2)`
` = (sqrt 5-2)/((sqrt5)^2 - (2)^2 )`
`=(sqrt5 -2)/(5-4)`
` = sqrt5 - 2`
Therefore,
`x - 1/x=sqrt5 +2 -(sqrt5 - 2)`
`= sqrt5 +2 - sqrt5 +2`
` = 2+2`
` = 4`
APPEARS IN
संबंधित प्रश्न
Rationalise the denominator of the following
`sqrt2/sqrt5`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Rationalise the denominator of the following
`(3sqrt2)/sqrt5`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt10 + sqrt15)/sqrt2`
`
Express the following with rational denominator:
`30/(5sqrt3 - 3sqrt5)`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(3 - sqrt5)/(3 + 2sqrt5)`
Write the reciprocal of \[5 + \sqrt{2}\].
If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then
Simplify the following expression:
`(sqrt5-sqrt2)(sqrt5+sqrt2)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
