Advertisements
Advertisements
प्रश्न
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
पर्याय
\[2\sqrt{5}\]
4
2
\[\sqrt{5}\]
Advertisements
उत्तर
Given that. `x=sqrt5 +2 ` Hence `1/x`is given as
`1/x = 1/(sqrt5+2)`.We need to find `x - 1/x`
We know that rationalization factor for `sqrt5+2` is`sqrt5-2`. We will multiply numerator and denominator of the given expression\`1/(sqrt5 +2)` by`sqrt5 - 2`, to get
`1/x = 1/(sqrt5+2 ) xx (sqrt5 - 2)/(sqrt5 -2)`
` = (sqrt 5-2)/((sqrt5)^2 - (2)^2 )`
`=(sqrt5 -2)/(5-4)`
` = sqrt5 - 2`
Therefore,
`x - 1/x=sqrt5 +2 -(sqrt5 - 2)`
`= sqrt5 +2 - sqrt5 +2`
` = 2+2`
` = 4`
APPEARS IN
संबंधित प्रश्न
Simplify of the following:
`root(4)1250/root(4)2`
Simplify the following expressions:
`(3 + sqrt3)(5 - sqrt2)`
Rationalise the denominator of the following
`(3sqrt2)/sqrt5`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
if `x = (sqrt3 + 1)/2` find the value of `4x^2 +2x^2 - 8x + 7`
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
The rationalisation factor of \[\sqrt{3}\] is
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
