Advertisements
Advertisements
प्रश्न
Represent `sqrt9.3` on the number line.
Advertisements
उत्तर

Draw a line segment AB = 9.3 units and extend it to C such that BC = 1 unit.
Find the midpoint of AC and mark it as O.
Draw a semicircle with O as the centre and AO as the radius.
Draw BD ⊥ AC.
Draw an arc with B as the centre and BD and produce radius AC at E such that BE = BD = `sqrt9.3` units.
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(3 + sqrt3)(5 - sqrt2)`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Express of the following with rational denominator:
`1/(sqrt6 - sqrt5)`
\[\sqrt{10} \times \sqrt{15}\] is equal to
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
The rationalisation factor of \[2 + \sqrt{3}\] is
Simplify the following expression:
`(3+sqrt3)(3-sqrt3)`
The value of `(sqrt(32) + sqrt(48))/(sqrt(8) + sqrt(12))` is equal to ______.
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
