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प्रश्न
Represent `sqrt9.3` on the number line.
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उत्तर
Draw a line segment AB = 9.3 units and extend it to C such that BC = 1 unit.
Find the midpoint of AC and mark it as O.
Draw a semicircle with O as the centre and AO as the radius.
Draw BD ⊥ AC.
Draw an arc with B as the centre and BD and produce radius AC at E such that BE = BD = `sqrt9.3` units.
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संबंधित प्रश्न
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt2 - 1)/sqrt5`
Express the following with rational denominator:
`(3sqrt2 + 1)/(2sqrt5 - 3)`
Rationales the denominator and simplify:
`(4sqrt3 + 5sqrt2)/(sqrt48 + sqrt18)`
In the following determine rational numbers a and b:
`(5 + 3sqrt3)/(7 + 4sqrt3) = a + bsqrt3`
In the following determine rational numbers a and b:
`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`
Simplify `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + sqrt12/(sqrt3 - sqrt2)`
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
