Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Advertisements
उत्तर
We know that rationalization factor for `1/sqrta` is `sqrta`.We will multiply numerator and denominator of the given expression `(sqrt3 + 1)/sqrt2` by `sqrt2` to get
`(sqrt3 + 1)/sqrt2 xx sqrt2/sqrt2 = (sqrt2 xx sqrt3 + sqrt2)/(sqrt2 xx sqrt2)`
`= (sqrt6 + sqrt2)/2`
Hence the given expression is simplified to `(sqrt6 + sqrt2)/2`
APPEARS IN
संबंधित प्रश्न
Simplify the following expression:
`(3+sqrt3)(2+sqrt2)`
Express the following with rational denominator:
`(3sqrt2 + 1)/(2sqrt5 - 3)`
Simplify:
`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`
Simplify `(7 + 3sqrt5)/(3 + sqrt5) - (7 - 3sqrt5)/(3 - sqrt5)`
\[\sqrt{10} \times \sqrt{15}\] is equal to
Classify the following number as rational or irrational:
2π
`1/(sqrt(9) - sqrt(8))` is equal to ______.
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
Simplify:
`(256)^(-(4^((-3)/2))`
