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प्रश्न
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
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उत्तर
We know that rationalization factor for `1/sqrta` is `sqrta`.We will multiply numerator and denominator of the given expression `(sqrt3 + 1)/sqrt2` by `sqrt2` to get
`(sqrt3 + 1)/sqrt2 xx sqrt2/sqrt2 = (sqrt2 xx sqrt3 + sqrt2)/(sqrt2 xx sqrt2)`
`= (sqrt6 + sqrt2)/2`
Hence the given expression is simplified to `(sqrt6 + sqrt2)/2`
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संबंधित प्रश्न
Rationales the denominator and simplify:
`(2sqrt6 - sqrt5)/(3sqrt5 - 2sqrt6)`
Simplify:
`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].
The rationalisation factor of \[\sqrt{3}\] is
Rationalise the denominator of the following:
`(3sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3))`
Find the value of a and b in the following:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
