Advertisements
Advertisements
प्रश्न
The rationalisation factor of \[\sqrt{3}\] is
पर्याय
\[- \sqrt{3}\]
\[\frac{1}{\sqrt{3}}\]
\[2\sqrt{3}\]
\[- 2\sqrt{3}\]
Advertisements
उत्तर
We know that rationalization factor for `sqrta` is `1/sqrta`. Hence rationalization factor of `sqrt3` is `1/sqrt3`.
APPEARS IN
संबंधित प्रश्न
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
if `x = (sqrt3 + 1)/2` find the value of `4x^2 +2x^2 - 8x + 7`
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
Write the value of \[\left( 2 + \sqrt{3} \right) \left( 2 - \sqrt{3} \right) .\]
If\[\frac{\sqrt{3} - 1}{\sqrt{3} + 1} = x + y\sqrt{3},\] find the values of x and y.
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
Rationalise the denominator of the following:
`sqrt(6)/(sqrt(2) + sqrt(3))`
Find the value of a and b in the following:
`(3 - sqrt(5))/(3 + 2sqrt(5)) = asqrt(5) - 19/11`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
