Advertisements
Advertisements
प्रश्न
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
Advertisements
उत्तर
`64^(-1/3)[64^(1/3) - 64^(2/3)] = (4^3)^(-1/3)[(4^3)^(1/3) - (4^3)^(2/3)]` ...[∵ (am)n = amn]
= `4^(3 xx - 1/3) (4^(3 xx 1/3) - 4^(3 xx 2/3))`
= 4–1(4 – 42)
= `1/4(4 - 16)`
= `-12/4`
= – 3
APPEARS IN
संबंधित प्रश्न
Recall, π is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, π = `c/d`. This seems to contradict the fact that π is irrational. How will you resolve this contradiction?
Rationalise the denominator of the following:
`1/sqrt7`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt2 - 1)/sqrt5`
Rationales the denominator and simplify:
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`
In the following determine rational numbers a and b:
`(4 + sqrt2)/(2 + sqrt2) = n - sqrtb`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
\[\sqrt{10} \times \sqrt{15}\] is equal to
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
