Advertisements
Advertisements
प्रश्न
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt5 + 1)/sqrt2`
Advertisements
उत्तर
We know that rationalization factor of the denominator is `sqrt2`.We will multiply numerator and denominator of the given expression `(sqrt5 + 1)/sqrt2` by `sqrt2` to get
`(sqrt5 + 1)/sqrt2 xx sqrt2/sqrt2 = (sqrt10 + sqrt2)/(sqrt2 xx sqrt2)`
`= (sqrt10 + sqrt2)/2`
`= (3.162 + 1.414)/2`
= 4.576/2
= 2.288
The value of expression 2.288 can be round off to three decimal places as 2.288.
Hence the given expression is simplified to 2.288.
APPEARS IN
संबंधित प्रश्न
Simplify the following expression:
`(3+sqrt3)(2+sqrt2)`
Simplify of the following:
`root(3)4 xx root(3)16`
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Rationales the denominator and simplify:
`(1 + sqrt2)/(3 - 2sqrt2)`
Simplify `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + sqrt12/(sqrt3 - sqrt2)`
If \[a = \sqrt{2} + 1\],then find the value of \[a - \frac{1}{a}\].
Classify the following number as rational or irrational:
`1/sqrt2`
Rationalise the denominator of the following:
`1/(sqrt7-sqrt6)`
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
The value of `(sqrt(32) + sqrt(48))/(sqrt(8) + sqrt(12))` is equal to ______.
