Advertisements
Advertisements
प्रश्न
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
Advertisements
उत्तर
`4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
⇒ `4 xx (216)^(2/3) + (256)^(3/4) + 2 xx (243)^(1/5)`
⇒ `4 xx (6^3)^(2/3) + (4^4)^(3/4) + 2 xx (3^5)^(1/5)`
By law indices (am)n = amn
⇒ 4 × (6)2 + (4)2 + 2 × (3)1
⇒ 4 × 36 + (4)3 + 2 × (3)1
= 144 + 64 + 6
= 214
APPEARS IN
संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Simplify the following expression:
`(3+sqrt3)(2+sqrt2)`
Represent `sqrt9.3` on the number line.
Simplify the following expressions:
`(3 + sqrt3)(3 - sqrt3)`
In the following determine rational numbers a and b:
`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
Simplify the following:
`sqrt(24)/8 + sqrt(54)/9`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Rationalise the denominator of the following:
`(4sqrt(3) + 5sqrt(2))/(sqrt(48) + sqrt(18))`
