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Question
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
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Solution
`4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
⇒ `4 xx (216)^(2/3) + (256)^(3/4) + 2 xx (243)^(1/5)`
⇒ `4 xx (6^3)^(2/3) + (4^4)^(3/4) + 2 xx (3^5)^(1/5)`
By law indices (am)n = amn
⇒ 4 × (6)2 + (4)2 + 2 × (3)1
⇒ 4 × 36 + (4)3 + 2 × (3)1
= 144 + 64 + 6
= 214
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