Advertisements
Advertisements
प्रश्न
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
Advertisements
उत्तर
`4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
⇒ `4 xx (216)^(2/3) + (256)^(3/4) + 2 xx (243)^(1/5)`
⇒ `4 xx (6^3)^(2/3) + (4^4)^(3/4) + 2 xx (3^5)^(1/5)`
By law indices (am)n = amn
⇒ 4 × (6)2 + (4)2 + 2 × (3)1
⇒ 4 × 36 + (4)3 + 2 × (3)1
= 144 + 64 + 6
= 214
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(sqrt3 + sqrt7)^2`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Simplify
`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`
In the following determine rational numbers a and b:
`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`
If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Value of `root(4)((81)^-2)` is ______.
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Simplify the following:
`sqrt(24)/8 + sqrt(54)/9`
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
