Advertisements
Advertisements
प्रश्न
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Advertisements
उत्तर
We know that rationalization factor for `sqrt(a^2 + b^2) + a` is `sqrt(a^2 + b^2) - a`. We will multiply numerator and denominator of the given expression `b^2/(sqrt(a^2 + b^2) + a) ` by `sqrt(a^2 + b^2) - a` to get
`b^2/(sqrt(a^2 + b^2) + a) xx (sqrt(a^2 + b^2) - a)/(sqrt(a^2 + b^2) - a) = (b^2(sqrt(a^2 + b^2)))/(sqrt(a^2 + b^2) - a^2)`
`= (b^2 (sqrt(a^2 + b^2) - a))/(a^2 + b^2 - a^2)`
`= (b^2(sqrt(a^2 + b^2) - a))/b^2`
`= sqrt(a^2 + b^2) - a`
Hence the given expression is simplified with rational denominator to `sqrt(a^2 + b^2) - a`
APPEARS IN
संबंधित प्रश्न
Represent `sqrt9.3` on the number line.
Rationalise the denominator of the following
`sqrt2/sqrt5`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Rationales the denominator and simplify:
`(3 - sqrt2)/(3 + sqrt2)`
Simplify:
`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].
`root(4)root(3)(2^2)` equals to ______.
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
Simplify:
`(1/27)^((-2)/3)`
