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प्रश्न
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
विकल्प
\[\sqrt[5]{36}\]
\[\sqrt[5]{6 \times 0}\]
\[\sqrt[5]{6}\]
\[\sqrt[5]{12}\]
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उत्तर
Given that`5sqrt6 xx 5sqrt6`, it can be simplified as
`5sqrt6 xx 5 sqrt6 = 5 sqrt(6xx6)`
` = 5sqrt36`
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संबंधित प्रश्न
Represent `sqrt9.3` on the number line.
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Express the following with rational denominator:
`(sqrt3 + 1)/(2sqrt2 - sqrt3)`
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`(5 + 3sqrt3)/(7 + 4sqrt3) = a + bsqrt3`
Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]
Rationalise the denominator of the following:
`1/(sqrt7-sqrt6)`
Simplify the following:
`sqrt(24)/8 + sqrt(54)/9`
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
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`6/sqrt(6)`
