Advertisements
Advertisements
प्रश्न
Simplify the following expressions:
`(4 + sqrt7)(3 + sqrt2)`
Advertisements
उत्तर
We can simplify the expression `(4 + sqrt7)(3 + sqrt2)` as
`(4 + sqrt7)(3 + sqrt2) = 4 xx 3 + 4 xx sqrt2 + 3 xx sqrt7 + sqrt7 xx sqrt2 `
`= 12 + 4sqrt2 + 3sqrt7 + sqrt(7xx2)`
`= 12 + 4sqrt2 + 3sqrt7 + sqrt14`
Hence the value of the expression is `12 + 4sqrt2 + 3sqrt7 + sqrt14`
APPEARS IN
संबंधित प्रश्न
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(3 - sqrt5)/(3 + 2sqrt5)`
The rationalisation factor of \[\sqrt{3}\] is
Classify the following number as rational or irrational:
`1/sqrt2`
Classify the following number as rational or irrational:
2π
Simplify the following:
`3/sqrt(8) + 1/sqrt(2)`
Simplify the following:
`(2sqrt(3))/3 - sqrt(3)/6`
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
