Advertisements
Advertisements
प्रश्न
Simplify:
`(8^(1/3) xx 16^(1/3))/(32^(-1/3))`
Advertisements
उत्तर
`(8^(1/3) xx 16^(1/3))/(32^(- 1/3)) = ((2^3)^(1/3) xx (2^4)^(1/3))/((2^5)^(-1/3))` ...[∵ (am)n = amn]
= `(2^(3 xx 1/3) xx 2^(4 xx 1/3))/(2^(5 xx -1/3))`
= `(2^(3/3 + 4/3))/(2^(-5/3))` ...`[∵ a^m/a^n = a^(m - n)]`
= `2^(7/3)/(2^(-5/3))`
= `2^(7/3 + 5/3)`
= `2^(12/3)`
= 24
= 16
APPEARS IN
संबंधित प्रश्न
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(1 + sqrt2)/(3 - 2sqrt2)`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
\[\sqrt{10} \times \sqrt{15}\] is equal to
The rationalisation factor of \[2 + \sqrt{3}\] is
Value of (256)0.16 × (256)0.09 is ______.
Simplify the following:
`3/sqrt(8) + 1/sqrt(2)`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
