Advertisements
Advertisements
प्रश्न
Represent `sqrt9.3` on the number line.
Advertisements
उत्तर
Draw a line segment AB = 9.3 units and extend it to C such that BC = 1 unit.
Find the midpoint of AC and mark it as O.
Draw a semicircle with O as the centre and AO as the radius.
Draw BD ⊥ AC.
Draw an arc with B as the centre and BD and produce radius AC at E such that BE = BD = `sqrt9.3` units.
APPEARS IN
संबंधित प्रश्न
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Rationales the denominator and simplify:
`(1 + sqrt2)/(3 - 2sqrt2)`
Rationales the denominator and simplify:
`(4sqrt3 + 5sqrt2)/(sqrt48 + sqrt18)`
In the following determine rational numbers a and b:
`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
Value of (256)0.16 × (256)0.09 is ______.
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Rationalise the denominator of the following:
`(4sqrt(3) + 5sqrt(2))/(sqrt(48) + sqrt(18))`
