Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
Advertisements
उत्तर
Let `E = 16/(sqrt(41) - 5)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(41) + 5`,
`E = 16/(sqrt(41) - 5) xx (sqrt(41) + 5)/(sqrt(41) + 5)`
= `(16(sqrt(41) + 5))/((sqrt(41))^2 - (5)^2` ...[Using identity, (a – b)(a + b) = a2 – b2]
= `(16(sqrt(41) + 5))/(41 - 25)`
= `(16(sqrt(41) + 5))/16`
= `sqrt(41) + 5`
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt5 + 1)/sqrt2`
Express the following with rational denominator:
`(6 - 4sqrt2)/(6 + 4sqrt2)`
In the following determine rational numbers a and b:
`(4 + sqrt2)/(2 + sqrt2) = n - sqrtb`
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then
Simplify the following expression:
`(3+sqrt3)(3-sqrt3)`
Rationalise the denominator of the following:
`1/(sqrt5+sqrt2)`
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
