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प्रश्न
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
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उत्तर
Let `E = 16/(sqrt(41) - 5)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(41) + 5`,
`E = 16/(sqrt(41) - 5) xx (sqrt(41) + 5)/(sqrt(41) + 5)`
= `(16(sqrt(41) + 5))/((sqrt(41))^2 - (5)^2` ...[Using identity, (a – b)(a + b) = a2 – b2]
= `(16(sqrt(41) + 5))/(41 - 25)`
= `(16(sqrt(41) + 5))/16`
= `sqrt(41) + 5`
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