Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
Advertisements
उत्तर
Let `E = 16/(sqrt(41) - 5)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(41) + 5`,
`E = 16/(sqrt(41) - 5) xx (sqrt(41) + 5)/(sqrt(41) + 5)`
= `(16(sqrt(41) + 5))/((sqrt(41))^2 - (5)^2` ...[Using identity, (a – b)(a + b) = a2 – b2]
= `(16(sqrt(41) + 5))/(41 - 25)`
= `(16(sqrt(41) + 5))/16`
= `sqrt(41) + 5`
APPEARS IN
संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Simplify the following expressions:
`(4 + sqrt7)(3 + sqrt2)`
Simplify the following expressions:
`(3 + sqrt3)(5 - sqrt2)`
Express the following with rational denominator:
`(sqrt3 + 1)/(2sqrt2 - sqrt3)`
Simplify `(7 + 3sqrt5)/(3 + sqrt5) - (7 - 3sqrt5)/(3 - sqrt5)`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
Write the value of \[\left( 2 + \sqrt{3} \right) \left( 2 - \sqrt{3} \right) .\]
Simplify \[\sqrt{3 - 2\sqrt{2}}\].
Value of `root(4)((81)^-2)` is ______.
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
