Advertisements
Advertisements
Question
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
Advertisements
Solution
Let `E = 16/(sqrt(41) - 5)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(41) + 5`,
`E = 16/(sqrt(41) - 5) xx (sqrt(41) + 5)/(sqrt(41) + 5)`
= `(16(sqrt(41) + 5))/((sqrt(41))^2 - (5)^2` ...[Using identity, (a – b)(a + b) = a2 – b2]
= `(16(sqrt(41) + 5))/(41 - 25)`
= `(16(sqrt(41) + 5))/16`
= `sqrt(41) + 5`
APPEARS IN
RELATED QUESTIONS
Simplify of the following:
`root(3)4 xx root(3)16`
Simplify the following expressions:
`(3 + sqrt3)(5 - sqrt2)`
In the following determine rational numbers a and b:
`(5 + 3sqrt3)/(7 + 4sqrt3) = a + bsqrt3`
In the following determine rational numbers a and b:
`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`
if `x = 2 + sqrt3`,find the value of `x^2 + 1/x^2`
Simplify the following expression:
`(sqrt5-sqrt2)(sqrt5+sqrt2)`
Value of (256)0.16 × (256)0.09 is ______.
Simplify the following:
`(2sqrt(3))/3 - sqrt(3)/6`
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
