Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
Advertisements
उत्तर
Let `E = 16/(sqrt(41) - 5)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(41) + 5`,
`E = 16/(sqrt(41) - 5) xx (sqrt(41) + 5)/(sqrt(41) + 5)`
= `(16(sqrt(41) + 5))/((sqrt(41))^2 - (5)^2` ...[Using identity, (a – b)(a + b) = a2 – b2]
= `(16(sqrt(41) + 5))/(41 - 25)`
= `(16(sqrt(41) + 5))/16`
= `sqrt(41) + 5`
APPEARS IN
संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Rationalise the denominator of the following:
`1/sqrt7`
Simplify the following expressions:
`(5 + sqrt7)(5 - sqrt7)`
Simplify the following expressions:
`(sqrt3 + sqrt7)^2`
Rationalise the denominator of the following
`sqrt2/sqrt5`
In the following determine rational numbers a and b:
`(5 + 3sqrt3)/(7 + 4sqrt3) = a + bsqrt3`
Simplify the following expression:
`(3+sqrt3)(3-sqrt3)`
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Simplify:
`(256)^(-(4^((-3)/2))`
