Question

Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]

Answer 1

We know that rationalization factor for `3sqrt2 +2sqrt3` and  `sqrt3-sqrt2`are `3sqrt2 - 2sqrt3`and   `sqrt3 +sqrt2`respectively. We will multiply numerator and denominator of the given expression  `(3sqrt2 -2sqrt3)/ (3sqrt2 +2sqrt3)`  and  `sqrt12/(sqrt3-sqrt2)`by `3sqrt2-2sqrt3`and `sqrt3 +sqrt2`respectively, to get

`(3sqrt2 -2sqrt3)/ (3sqrt2 +2sqrt3) xx (3sqrt2 -2sqrt3)/ (3sqrt2 -2sqrt3) +sqrt12/(sqrt3-sqrt2) xx (sqrt3 +sqrt2)/(sqrt3 +sqrt2) =((3sqrt2)^2+(2sqrt3)^2  - 2xx 3 sqrt2 xx 2sqrt3)/((3sqrt2)^2 -( 2sqrt3)^2 ) +(sqrt36+sqrt24)/((sqrt3)^2-(sqrt2)^2)`

`= (18+12-12sqrt6)/(18-12) +(6+sqrt24)/(3-2)`

`= (30-12sqrt6 +36 +12sqrt6)/6`

`=66/6`

`=11`