Advertisements
Advertisements
प्रश्न
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
Advertisements
उत्तर
We know that rationalization factor for `sqrt5 - sqrt3` is `sqrt5 + sqrt3`. We will multiply denominator and numerator of the given expression `6/(sqrt5 - sqrt3)` by `sqrt5 + sqrt3` to get
`6/(sqrt5 - sqrt3) xx (sqrt5 + sqrt3)/(sqrt5 + sqrt3) = (6sqrt5 + 6sqrt3)/((sqrt5)^2 - (sqrt3)^3)`
`= (6sqrt5 + 6sqrt3)/(5 - 3)`
`= (6sqrt5 + 6sqrt3)/2`
`= 3sqrt5 + 3sqrt3`
Putting the values of `sqrt5` and `sqrt3` we get
`3sqrt5 + 3sqrt3 = 3(2.236) + 3(1.732)`
= 6.708 + 5.196
= 11.904
Hence value of the given expression is 11.904
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(2sqrt5 + 3sqrt2)^2`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Rationalise the denominator of the following
`(3sqrt2)/sqrt5`
Express the following with rational denominator:
`30/(5sqrt3 - 3sqrt5)`
\[\sqrt{10} \times \sqrt{15}\] is equal to
The rationalisation factor of \[2 + \sqrt{3}\] is
Simplify the following expression:
`(sqrt5-sqrt2)(sqrt5+sqrt2)`
Rationalise the denominator of the following:
`1/(sqrt7-2)`
Find the value of a and b in the following:
`(3 - sqrt(5))/(3 + 2sqrt(5)) = asqrt(5) - 19/11`
Simplify:
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2))`
