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प्रश्न
The rationalisation factor of \[\sqrt{3}\] is
विकल्प
\[- \sqrt{3}\]
\[\frac{1}{\sqrt{3}}\]
\[2\sqrt{3}\]
\[- 2\sqrt{3}\]
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उत्तर
We know that rationalization factor for `sqrta` is `1/sqrta`. Hence rationalization factor of `sqrt3` is `1/sqrt3`.
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संबंधित प्रश्न
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
In the following determine rational numbers a and b:
`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`
The rationalisation factor of \[2 + \sqrt{3}\] is
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Rationalise the denominator of the following:
`sqrt(6)/(sqrt(2) + sqrt(3))`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`.
