Advertisements
Advertisements
Question
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Advertisements
Solution
We know that rationalization factor for `sqrt(a^2 + b^2) + a` is `sqrt(a^2 + b^2) - a`. We will multiply numerator and denominator of the given expression `b^2/(sqrt(a^2 + b^2) + a) ` by `sqrt(a^2 + b^2) - a` to get
`b^2/(sqrt(a^2 + b^2) + a) xx (sqrt(a^2 + b^2) - a)/(sqrt(a^2 + b^2) - a) = (b^2(sqrt(a^2 + b^2)))/(sqrt(a^2 + b^2) - a^2)`
`= (b^2 (sqrt(a^2 + b^2) - a))/(a^2 + b^2 - a^2)`
`= (b^2(sqrt(a^2 + b^2) - a))/b^2`
`= sqrt(a^2 + b^2) - a`
Hence the given expression is simplified with rational denominator to `sqrt(a^2 + b^2) - a`
APPEARS IN
RELATED QUESTIONS
Simplify the following expressions:
`(sqrt5 - sqrt3)^2`
Rationalise the denominator of the following:
`3/(2sqrt5)`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Express of the following with rational denominator:
`1/(sqrt6 - sqrt5)`
In the following determine rational numbers a and b:
`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`
In the following determine rational numbers a and b:
`(3 + sqrt2)/(3 - sqrt2) = a + bsqrt2`
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Rationalise the denominator of the following:
`(3sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3))`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
Simplify:
`(8^(1/3) xx 16^(1/3))/(32^(-1/3))`
