Advertisements
Advertisements
Question
Simplify the following expression:
`(sqrt5+sqrt2)^2`
Advertisements
Solution
The given expression is `(sqrt5 + sqrt2)^2`
We know that (a + b)2 = a2 + b2 + 2ab
⇒ `(sqrt5 + sqrt2)^2 =(sqrt5)^2 + (sqrt2)^2 + 2 xx sqrt5 xx sqrt2`
⇒ `(sqrt5 + sqrt2)^2 = 5 + 2 + 2sqrt10`
∴ `(sqrt5 + sqrt2)^2 = 7 + 2sqrt10`
APPEARS IN
RELATED QUESTIONS
Classify the following numbers as rational or irrational:
`2-sqrt5`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
In the following determine rational numbers a and b:
`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]
Write the rationalisation factor of \[\sqrt{5} - 2\].
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
