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प्रश्न
Simplify the following expression:
`(sqrt5+sqrt2)^2`
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उत्तर
The given expression is `(sqrt5 + sqrt2)^2`
We know that (a + b)2 = a2 + b2 + 2ab
⇒ `(sqrt5 + sqrt2)^2 =(sqrt5)^2 + (sqrt2)^2 + 2 xx sqrt5 xx sqrt2`
⇒ `(sqrt5 + sqrt2)^2 = 5 + 2 + 2sqrt10`
∴ `(sqrt5 + sqrt2)^2 = 7 + 2sqrt10`
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संबंधित प्रश्न
Rationalise the denominator of the following:
`1/sqrt7`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt10 + sqrt15)/sqrt2`
`
Simplify:
`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
Value of (256)0.16 × (256)0.09 is ______.
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
Simplify:
`(1/27)^((-2)/3)`
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`(256)^(-(4^((-3)/2))`
