Advertisements
Advertisements
प्रश्न
Simplify the following expression:
`(sqrt5+sqrt2)^2`
Advertisements
उत्तर
The given expression is `(sqrt5 + sqrt2)^2`
We know that (a + b)2 = a2 + b2 + 2ab
⇒ `(sqrt5 + sqrt2)^2 =(sqrt5)^2 + (sqrt2)^2 + 2 xx sqrt5 xx sqrt2`
⇒ `(sqrt5 + sqrt2)^2 = 5 + 2 + 2sqrt10`
∴ `(sqrt5 + sqrt2)^2 = 7 + 2sqrt10`
APPEARS IN
संबंधित प्रश्न
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt10 + sqrt15)/sqrt2`
`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(1 + sqrt2)/(3 - 2sqrt2)`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].
Rationalise the denominator of the following:
`1/(sqrt7-2)`
The value of `(sqrt(32) + sqrt(48))/(sqrt(8) + sqrt(12))` is equal to ______.
Value of (256)0.16 × (256)0.09 is ______.
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
Find the value of a and b in the following:
`(3 - sqrt(5))/(3 + 2sqrt(5)) = asqrt(5) - 19/11`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
