Advertisements
Advertisements
प्रश्न
Simplify:
`(256)^(-(4^((-3)/2))`
Advertisements
उत्तर
`(256)^(-(4^(-3/2))) = (256)^(-(4)^(-3/2)`
= `(256)^(-(2^2)^(-3/2))`
= `(256)^(-(2^(2 xx -3/2))` ...`[∵ b^((a^m)^n) = b^(a^(mn))]`
= `(256)^(-(2^-3))`
= `(2^8)^(-(1/2^3)`
= `(2^8)^(-1/8)`
= `2^(8 xx -1/8)`
= `2^-1`
= `1/2`
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(3 + sqrt3)(3 - sqrt3)`
Simplify the following expressions:
`(sqrt5 - sqrt3)^2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt2 - 1)/sqrt5`
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
The rationalisation factor of \[\sqrt{3}\] is
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
