Advertisements
Advertisements
Question
Rationalise the denominator of the following:
`1/sqrt7`
Advertisements
Solution
The given number is `1/sqrt7`
On rationalising the denominator
⇒ `1/sqrt7 = 1/sqrt7 xx sqrt7/sqrt7`
∴ `1/sqrt7 = sqrt7/7`
APPEARS IN
RELATED QUESTIONS
Simplify the following expressions:
`(11 + sqrt11)(11 - sqrt11)`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
Express the following with rational denominator:
`1/(3 + sqrt2)`
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Rationales the denominator and simplify:
`(3 - sqrt2)/(3 + sqrt2)`
In the following determine rational numbers a and b:
`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Rationalise the denominator of the following:
`sqrt(40)/sqrt(3)`
Find the value of a and b in the following:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`
