Advertisements
Advertisements
Question
Rationalise the denominator of the following:
`1/sqrt7`
Advertisements
Solution
The given number is `1/sqrt7`
On rationalising the denominator
⇒ `1/sqrt7 = 1/sqrt7 xx sqrt7/sqrt7`
∴ `1/sqrt7 = sqrt7/7`
APPEARS IN
RELATED QUESTIONS
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt5 + 1)/sqrt2`
Write the rationalisation factor of \[\sqrt{5} - 2\].
If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].
Classify the following number as rational or irrational:
2π
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
Simplify:
`(256)^(-(4^((-3)/2))`
