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Question
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
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Solution
We know that rationalization factor of the denominator is `sqrt3`. We will multiply numerator and denominator of the given expression `2/sqrt3` by `sqrt3` to get
`2/sqrt3 xx sqrt3/sqrt3 = (2 xx sqrt3)/(sqrt3 xx sqrt3)`
`= (2sqrt3)/3`
`= (2 xx 1.732)/3`
`= 3.4641/3`
= 1.1547
The value of expression 1.1547 can be round off to three decimal places as 1.155
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