Advertisements
Advertisements
प्रश्न
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
Advertisements
उत्तर
We know that rationalization factor of the denominator is `sqrt3`. We will multiply numerator and denominator of the given expression `2/sqrt3` by `sqrt3` to get
`2/sqrt3 xx sqrt3/sqrt3 = (2 xx sqrt3)/(sqrt3 xx sqrt3)`
`= (2sqrt3)/3`
`= (2 xx 1.732)/3`
`= 3.4641/3`
= 1.1547
The value of expression 1.1547 can be round off to three decimal places as 1.155
APPEARS IN
संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Simplify the following expressions:
`(5 + sqrt7)(5 - sqrt7)`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
Rationales the denominator and simplify:
`(1 + sqrt2)/(3 - 2sqrt2)`
The rationalisation factor of \[\sqrt{3}\] is
Simplify the following expression:
`(sqrt5+sqrt2)^2`
Find the value of a and b in the following:
`(3 - sqrt(5))/(3 + 2sqrt(5)) = asqrt(5) - 19/11`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`1/(sqrt(3) + sqrt(2))`
Simplify:
`(1/27)^((-2)/3)`
