Advertisements
Advertisements
प्रश्न
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
Advertisements
उत्तर
We know that rationalization factor of the denominator is `sqrt3`. We will multiply numerator and denominator of the given expression `2/sqrt3` by `sqrt3` to get
`2/sqrt3 xx sqrt3/sqrt3 = (2 xx sqrt3)/(sqrt3 xx sqrt3)`
`= (2sqrt3)/3`
`= (2 xx 1.732)/3`
`= 3.4641/3`
= 1.1547
The value of expression 1.1547 can be round off to three decimal places as 1.155
APPEARS IN
संबंधित प्रश्न
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Rationales the denominator and simplify:
`(4sqrt3 + 5sqrt2)/(sqrt48 + sqrt18)`
Simplify
`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
Rationalise the denominator of the following:
`1/(sqrt7-2)`
Value of (256)0.16 × (256)0.09 is ______.
Simplify the following:
`3/sqrt(8) + 1/sqrt(2)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
