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Question
Simplify:
`(1/27)^((-2)/3)`
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Solution
`(1/27)^((-2)/3) = (1/3^3)^((-2)/3)` ...`[∵ 1/a = a^-1]`
= `(3^-3)^((-2)/3)`
= `3^(-3 xx -2/3)` ...[∵ (am)n = amn]
= 32
= 9
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