Advertisements
Advertisements
Question
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
Advertisements
Solution
`[((625)^(-1/2))^((-1)/4)]^2 = [((25^2)^(-1/2))^(-1/4)]^2` ...[∵ (am)n = amn]
= `(25^-1)^(-1/4 xx 2)`
= `[(5^2)^-1]^(-1/4 xx 2)`
= `5^(-2 xx -1/4 xx 2)`
= 51
= 5
APPEARS IN
RELATED QUESTIONS
Represent `sqrt9.3` on the number line.
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
In the following determine rational numbers a and b:
`(3 + sqrt2)/(3 - sqrt2) = a + bsqrt2`
Rationalise the denominator of the following:
`1/(sqrt5+sqrt2)`
Value of (256)0.16 × (256)0.09 is ______.
Simplify the following:
`4sqrt(28) ÷ 3sqrt(7) ÷ root(3)(7)`
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
Rationalise the denominator of the following:
`(4sqrt(3) + 5sqrt(2))/(sqrt(48) + sqrt(18))`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
