Advertisements
Advertisements
प्रश्न
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
Advertisements
उत्तर
`[((625)^(-1/2))^((-1)/4)]^2 = [((25^2)^(-1/2))^(-1/4)]^2` ...[∵ (am)n = amn]
= `(25^-1)^(-1/4 xx 2)`
= `[(5^2)^-1]^(-1/4 xx 2)`
= `5^(-2 xx -1/4 xx 2)`
= 51
= 5
APPEARS IN
संबंधित प्रश्न
Simplify of the following:
`root(3)4 xx root(3)16`
Simplify the following expressions:
`(2sqrt5 + 3sqrt2)^2`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Express of the following with rational denominator:
`1/(sqrt6 - sqrt5)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(1 + sqrt2)/(3 - 2sqrt2)`
Simplify `(7 + 3sqrt5)/(3 + sqrt5) - (7 - 3sqrt5)/(3 - sqrt5)`
`root(4)root(3)(2^2)` equals to ______.
Value of (256)0.16 × (256)0.09 is ______.
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
