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प्रश्न
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
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उत्तर
`[((625)^(-1/2))^((-1)/4)]^2 = [((25^2)^(-1/2))^(-1/4)]^2` ...[∵ (am)n = amn]
= `(25^-1)^(-1/4 xx 2)`
= `[(5^2)^-1]^(-1/4 xx 2)`
= `5^(-2 xx -1/4 xx 2)`
= 51
= 5
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संबंधित प्रश्न
Rationalise the denominator of the following:
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Rationalise the denominator of the following
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Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
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Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
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Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
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Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
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Simplify:
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