Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following
`sqrt2/sqrt5`
Advertisements
उत्तर
We know that rationalization factor for `1/sqrta ` is `sqrta`. We willmultiply numerator and denominator of the given expression `sqrt2/sqrt5` by `sqrt5`, to get
`sqrt2/sqrt5 xx sqrt5/sqrt5 = (sqrt2 xx sqrt5)/(sqrt5 xx sqrt5)`
`= sqrt10/5`
Hence the given expression is simplified to `sqrt10/5`
APPEARS IN
संबंधित प्रश्न
Simplify
`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`
In the following determine rational numbers a and b:
`(4 + sqrt2)/(2 + sqrt2) = n - sqrtb`
Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
Value of (256)0.16 × (256)0.09 is ______.
Simplify the following:
`4sqrt12 xx 7sqrt6`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
