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प्रश्न
Rationalise the denominator of the following
`sqrt2/sqrt5`
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उत्तर
We know that rationalization factor for `1/sqrta ` is `sqrta`. We willmultiply numerator and denominator of the given expression `sqrt2/sqrt5` by `sqrt5`, to get
`sqrt2/sqrt5 xx sqrt5/sqrt5 = (sqrt2 xx sqrt5)/(sqrt5 xx sqrt5)`
`= sqrt10/5`
Hence the given expression is simplified to `sqrt10/5`
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संबंधित प्रश्न
Simplify of the following:
`root(3)4 xx root(3)16`
Simplify the following expressions:
`(sqrt3 + sqrt7)^2`
Express the following with rational denominator:
`(sqrt3 + 1)/(2sqrt2 - sqrt3)`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].
Classify the following number as rational or irrational:
`1/sqrt2`
Simplify the following:
`4sqrt(28) ÷ 3sqrt(7) ÷ root(3)(7)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
